创建自己的小题库
搜索
【单选题】
在胆囊造影时，为检查胆囊的收缩功能，让受检查者进食油煎荷包蛋是为了促进（）
A.
胆盐合成
B.
胆固醇合成
C.
促胃液素分泌
D.
缩胆囊素分泌
E.
迷走神经兴奋
手机使用
分享
复制链接
新浪微博
分享QQ
微信扫一扫
反馈
收藏
举报参考答案：
举一反三
【单选题】某病人,需作胆囊造影,检查前准备错误和一项是
A.
检查前1日午餐高脂肪餐,晚餐进无脂肪、低蛋白的清淡饮食
B.
检查前1日午餐进无脂肪低、高蛋白的清淡饮食、晚餐进高脂肪
C.
检查前当日早餐禁食
D.
检查时第一次摄片后如胆囊显影良好则进高脂肪餐
E.
30min后第二次摄取片观察
【单选题】有如下事件过程：Private Sub Form_Load() Show Dim Arr() As Variant Arr = Array(1, 3, 5, 7, 9, 11, 13, 15) Call converse(Arr) For i = 0 To 7 Print arr(i); Next iEnd Sub 以上程序的功能是，通过调用Converse过程，将数组Arr中的元素逆序存放并输出...
A.
Private Sub converse(dim a() as Variant ) Dim T For i = LBound(A) To UBound(A) T = a(i) a(i) = a(UBound(A) - i) a(UBound(A) - i) = T Next i End Sub
B.
Private Sub converse(dim a() as Variant) Dim T Dim J As Integer J = (LBound(A) + UBound(A)) / 2 For i = LBound(A) To J T = a(i) a(i) = a(UBound(A) - i) a(UBound(A) - i) = T Next i End Sub
C.
Private Sub converse(a() As Variant) Dim T For i = LBound(A) To UBound(A) T = a(i) a(i) = a(UBound(A) - i) a(UBound(A) - i) = T Next i End Sub
D.
Private Sub converse(a() As Variant) Dim T Dim J As Integer J = Int((LBound(A) + UBound(A)) / 2) For i = LBound(A) To J T = a(i) a(i) = a(UBound(A) - i) a(UBound(A) - i) = T Next i End Sub
相关题目：
【单选题】某病人,需作胆囊造影,检查前准备错误和一项是
A.
检查前1日午餐高脂肪餐,晚餐进无脂肪、低蛋白的清淡饮食
B.
检查前1日午餐进无脂肪低、高蛋白的清淡饮食、晚餐进高脂肪
C.
检查前当日早餐禁食
D.
检查时第一次摄片后如胆囊显影良好则进高脂肪餐
E.
30min后第二次摄取片观察
【单选题】有如下事件过程：Private Sub Form_Load() Show Dim Arr() As Variant Arr = Array(1, 3, 5, 7, 9, 11, 13, 15) Call converse(Arr) For i = 0 To 7 Print arr(i); Next iEnd Sub 以上程序的功能是，通过调用Converse过程，将数组Arr中的元素逆序存放并输出...
A.
Private Sub converse(dim a() as Variant ) Dim T For i = LBound(A) To UBound(A) T = a(i) a(i) = a(UBound(A) - i) a(UBound(A) - i) = T Next i End Sub
B.
Private Sub converse(dim a() as Variant) Dim T Dim J As Integer J = (LBound(A) + UBound(A)) / 2 For i = LBound(A) To J T = a(i) a(i) = a(UBound(A) - i) a(UBound(A) - i) = T Next i End Sub
C.
Private Sub converse(a() As Variant) Dim T For i = LBound(A) To UBound(A) T = a(i) a(i) = a(UBound(A) - i) a(UBound(A) - i) = T Next i End Sub
D.
Private Sub converse(a() As Variant) Dim T Dim J As Integer J = Int((LBound(A) + UBound(A)) / 2) For i = LBound(A) To J T = a(i) a(i) = a(UBound(A) - i) a(UBound(A) - i) = T Next i End Sub
参考解析：
AI解析
重新生成
题目纠错 0
发布
