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【单选题】
多器官功能衰竭发病过程中最容易和最早受损害的器官是
A.
肺
B.
肾
C.
肝
D.
消化道
E.
脑
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举报参考答案：
举一反三
【单选题】下列各脏器的表现哪项不符合多器官功能衰竭的诊断标准（）
A.
心血管--心电图明显失常，收缩压＜10.6kPa或低于平素血压的2／3，需要药物支持
B.
肺--呼吸率＞28次／分，呼吸困难，烦躁，需吸氧支持
C.
肾--每小时尿量＜20ml，或尿量持续增多
D.
血液--皮肤出血斑点，胃肠出血、咯血
E.
脑--意识障碍（Glasgow平分＜7）、瞳孔反应等失常
【单选题】有如下事件过程：Private Sub Form_Load() Show Dim Arr() As Variant Arr = Array(1, 3, 5, 7, 9, 11, 13, 15) Call converse(Arr) For i = 0 To 7 Print arr(i); Next iEnd Sub 以上程序的功能是，通过调用Converse过程，将数组Arr中的元素逆序存放并输出...
A.
Private Sub converse(dim a() as Variant ) Dim T For i = LBound(A) To UBound(A) T = a(i) a(i) = a(UBound(A) - i) a(UBound(A) - i) = T Next i End Sub
B.
Private Sub converse(dim a() as Variant) Dim T Dim J As Integer J = (LBound(A) + UBound(A)) / 2 For i = LBound(A) To J T = a(i) a(i) = a(UBound(A) - i) a(UBound(A) - i) = T Next i End Sub
C.
Private Sub converse(a() As Variant) Dim T For i = LBound(A) To UBound(A) T = a(i) a(i) = a(UBound(A) - i) a(UBound(A) - i) = T Next i End Sub
D.
Private Sub converse(a() As Variant) Dim T Dim J As Integer J = Int((LBound(A) + UBound(A)) / 2) For i = LBound(A) To J T = a(i) a(i) = a(UBound(A) - i) a(UBound(A) - i) = T Next i End Sub
相关题目：
【单选题】下列各脏器的表现哪项不符合多器官功能衰竭的诊断标准（）
A.
心血管--心电图明显失常，收缩压＜10.6kPa或低于平素血压的2／3，需要药物支持
B.
肺--呼吸率＞28次／分，呼吸困难，烦躁，需吸氧支持
C.
肾--每小时尿量＜20ml，或尿量持续增多
D.
血液--皮肤出血斑点，胃肠出血、咯血
E.
脑--意识障碍（Glasgow平分＜7）、瞳孔反应等失常
【单选题】有如下事件过程：Private Sub Form_Load() Show Dim Arr() As Variant Arr = Array(1, 3, 5, 7, 9, 11, 13, 15) Call converse(Arr) For i = 0 To 7 Print arr(i); Next iEnd Sub 以上程序的功能是，通过调用Converse过程，将数组Arr中的元素逆序存放并输出...
A.
Private Sub converse(dim a() as Variant ) Dim T For i = LBound(A) To UBound(A) T = a(i) a(i) = a(UBound(A) - i) a(UBound(A) - i) = T Next i End Sub
B.
Private Sub converse(dim a() as Variant) Dim T Dim J As Integer J = (LBound(A) + UBound(A)) / 2 For i = LBound(A) To J T = a(i) a(i) = a(UBound(A) - i) a(UBound(A) - i) = T Next i End Sub
C.
Private Sub converse(a() As Variant) Dim T For i = LBound(A) To UBound(A) T = a(i) a(i) = a(UBound(A) - i) a(UBound(A) - i) = T Next i End Sub
D.
Private Sub converse(a() As Variant) Dim T Dim J As Integer J = Int((LBound(A) + UBound(A)) / 2) For i = LBound(A) To J T = a(i) a(i) = a(UBound(A) - i) a(UBound(A) - i) = T Next i End Sub
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