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如图所示,匀强电场中三点A、B、C是一个三角形的三个顶点,∠ABC=∠CAB=30°,BC=2 3 m,已知电场线平行于△ABC所在的平面,一个带电荷量q=-2×10-6C的点电荷由A移到B的过程中,电势能增加1.2×10-5J,由B移到C的过程中电场力做功6×10-6J,下列说法正确的是( ) A.B、C两点的电势差UBC=3V B.A点的电势低于B点的电势 C.负电荷由C移到A的过程中,电势能增加 D.该电场的场强为1V/m
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