【简答题】![](https://cos-cdn.shuashuati.com/shuashuati-web/2024-0521-0905-00/logo-new-ad743.png)
如图所示,A、B两小球大小相同,A绝 缘且不带电,B带正电,其质量之比为1:3,现让A 球从光滑绝缘的四分之一圆弧轨道的项点由静止 释放,当与静止在轨道最低点的B球发生完全弹性 碰撞后,B球飞入右边的匀强电场区.场强方向水平向左,最终B球恰好落至离抛出点的正下方h处的 C点,已知圆弧轨道半径为R,为g.求:(1)碰撞后,A球离C点的最大竖直高度; (2)B球的最大水平位移;(3)B球受到的电场力F与重力G的大小之比.
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![](data:image/png;base64,iVBORw0KGgoAAAANSUhEUgAAACAAAAAgCAYAAABzenr0AAAA5ElEQVRYR2NkGGDAOMD2M+B0wKpVq9huv/jbxPD/fxwDA4MkhQ59zsDIuEhVgrkuLCzsF7JZOB3QOml5B8P//+UUWoyqnZGxszovsoI4B0xc9gyfzxmZmb2rcsK3IRvWMWm599///7fgcfTz6vwoKWId8B+f75kZGX0q8iK3kugAhur8KJRQxx0FE5fhdQC5UTPqgNEQGA2B0RAYDYHREBgNgaETAuTW96TqG7yt4tbRFhGRIQBqHTP9+8dIoDUMTxqk5AK8zXKYiaDWMYhNpANIaJYPdMdkwLtmpOZnctUPeDkAAP6tmiH1ggTLAAAAAElFTkSuQmCC)
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参考答案:
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参考解析:
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