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【简答题】
以下程序的功能是将多维数组a(1 To m,1 To n)中的元素转移到一个名为b(1 To n*m)的一维数组中，完成该程序。
OptionBase 1
Private Sub Command1_Click(Index As Integer)
Dima(1 To 20,1 To 10)
Dim b()
ReDimb(1 To 200)
For i=1 To 20
For j=1 To 10
A(i,j)=i*j
Next j
Next i
Tran a,20,10b
End Sub
Sub Tran(a()an,n,b())
Dim i As Integer
For i=1 To m
For j=1 To n
______=a(i,j)
Next j
Next i
End Sub
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参考答案：
举一反三
【单选题】以下对一维数组a的正确说明是：（）
A.
char a（10）；
B.
int a[]；
C.
int k＝5，a[k]；
D.
char a[3]={‘a’，’b’，’c’}；
【单选题】有如下事件过程：Private Sub Form_Load() Show Dim Arr() As Variant Arr = Array(1, 3, 5, 7, 9, 11, 13, 15) Call converse(Arr) For i = 0 To 7 Print arr(i); Next iEnd Sub 以上程序的功能是，通过调用Converse过程，将数组Arr中的元素逆序存放并输出...
A.
Private Sub converse(dim a() as Variant ) Dim T For i = LBound(A) To UBound(A) T = a(i) a(i) = a(UBound(A) - i) a(UBound(A) - i) = T Next i End Sub
B.
Private Sub converse(dim a() as Variant) Dim T Dim J As Integer J = (LBound(A) + UBound(A)) / 2 For i = LBound(A) To J T = a(i) a(i) = a(UBound(A) - i) a(UBound(A) - i) = T Next i End Sub
C.
Private Sub converse(a() As Variant) Dim T For i = LBound(A) To UBound(A) T = a(i) a(i) = a(UBound(A) - i) a(UBound(A) - i) = T Next i End Sub
D.
Private Sub converse(a() As Variant) Dim T Dim J As Integer J = Int((LBound(A) + UBound(A)) / 2) For i = LBound(A) To J T = a(i) a(i) = a(UBound(A) - i) a(UBound(A) - i) = T Next i End Sub
【单选题】下在是对一维数组s的初始化，其中不正确的是（ ）。
A.
char s[5]={“abc”};
B.
char s[5]={‘a’,’b’,’c’};
C.
char s[5]=””;
D.
char s[5]=”abcdef”;
【单选题】以下对一维数组a进行不正确初始化的是
A.
int a[10]＝(0,0,0,0);
B.
int a[10]＝{10*2};
C.
int a[10]＝{};
D.
int a[]＝{0};
相关题目：
【单选题】以下对一维数组a的正确说明是：（）
A.
char a（10）；
B.
int a[]；
C.
int k＝5，a[k]；
D.
char a[3]={‘a’，’b’，’c’}；
【单选题】有如下事件过程：Private Sub Form_Load() Show Dim Arr() As Variant Arr = Array(1, 3, 5, 7, 9, 11, 13, 15) Call converse(Arr) For i = 0 To 7 Print arr(i); Next iEnd Sub 以上程序的功能是，通过调用Converse过程，将数组Arr中的元素逆序存放并输出...
A.
Private Sub converse(dim a() as Variant ) Dim T For i = LBound(A) To UBound(A) T = a(i) a(i) = a(UBound(A) - i) a(UBound(A) - i) = T Next i End Sub
B.
Private Sub converse(dim a() as Variant) Dim T Dim J As Integer J = (LBound(A) + UBound(A)) / 2 For i = LBound(A) To J T = a(i) a(i) = a(UBound(A) - i) a(UBound(A) - i) = T Next i End Sub
C.
Private Sub converse(a() As Variant) Dim T For i = LBound(A) To UBound(A) T = a(i) a(i) = a(UBound(A) - i) a(UBound(A) - i) = T Next i End Sub
D.
Private Sub converse(a() As Variant) Dim T Dim J As Integer J = Int((LBound(A) + UBound(A)) / 2) For i = LBound(A) To J T = a(i) a(i) = a(UBound(A) - i) a(UBound(A) - i) = T Next i End Sub
【单选题】下在是对一维数组s的初始化，其中不正确的是（ ）。
A.
char s[5]={“abc”};
B.
char s[5]={‘a’,’b’,’c’};
C.
char s[5]=””;
D.
char s[5]=”abcdef”;
【单选题】以下对一维数组a进行不正确初始化的是
A.
int a[10]＝(0,0,0,0);
B.
int a[10]＝{10*2};
C.
int a[10]＝{};
D.
int a[]＝{0};
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