【判断题】![](https://cos-cdn.shuashuati.com/shuashuati-web/2024-0521-0905-00/logo-new-ad743.png)
DDZ一Ⅲ型调节器的微分时间TD的校验,调整比例度为实际的100%,当偏差为零时,用软手动使输出电流为4mA,然后将切换开关拨到“自动”位置,改变输入电流应变化0.25V(即输入信号从3V变化到3.25V),此时输出电流应变化1mA(从4mA到5mA),把微分时间迅速旋至被校验的某刻度,输出电流应达到14mA。同时启动秒表记时,调节器输出按指数规律下降,当下降到8.3mA时[即14-(14-5)×63.2%=8.3(mA)],停表计时,该时间即为微分时间常数T(min)。则微分时间按下式计算:TD=KDT。()
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