大学职业资格刷题搜题APP
创建自己的小题库
搜索
【单选题】
树突状细胞是目前所知功能最强的抗原提呈细胞，主要归因于此类细胞
A.
具有强大的吞噬能力
B.
高表达MHC-Ⅰ类分子
C.
数量巨大
D.
表达TCR直接识别抗原
E.
能显著刺激初始T细胞进行增殖
相关题库：医学免疫题库
手机使用
分享
复制链接
新浪微博
分享QQ
微信扫一扫
反馈
收藏
举报
参考答案：
举一反三
【单选题】对树突状细胞的论述,下列哪项错误:
A.
有 mIg
B.
是重要的抗原提呈细胞
C.
表达 MHC-II 类分子
D.
表达 MHC-I 类分子
E.
具有免疫调节作用
【多选题】关于树突状细胞，正确的是（）
A.
可与单核细胞有共同的祖细胞
B.
可与T细胞有共同的祖细胞
C.
广泛分布全身各脏器
D.
外周血，脾脏含量很少
E.
膜表面特异性抗原识别受体
【单选题】有如下事件过程：Private Sub Form_Load() Show Dim Arr() As Variant Arr = Array(1, 3, 5, 7, 9, 11, 13, 15) Call converse(Arr) For i = 0 To 7 Print arr(i); Next iEnd Sub 以上程序的功能是，通过调用Converse过程，将数组Arr中的元素逆序存放并输出...
A.
Private Sub converse(dim a() as Variant ) Dim T For i = LBound(A) To UBound(A) T = a(i) a(i) = a(UBound(A) - i) a(UBound(A) - i) = T Next i End Sub
B.
Private Sub converse(dim a() as Variant) Dim T Dim J As Integer J = (LBound(A) + UBound(A)) / 2 For i = LBound(A) To J T = a(i) a(i) = a(UBound(A) - i) a(UBound(A) - i) = T Next i End Sub
C.
Private Sub converse(a() As Variant) Dim T For i = LBound(A) To UBound(A) T = a(i) a(i) = a(UBound(A) - i) a(UBound(A) - i) = T Next i End Sub
D.
Private Sub converse(a() As Variant) Dim T Dim J As Integer J = Int((LBound(A) + UBound(A)) / 2) For i = LBound(A) To J T = a(i) a(i) = a(UBound(A) - i) a(UBound(A) - i) = T Next i End Sub
相关题目：
【单选题】对树突状细胞的论述,下列哪项错误:
A.
有 mIg
B.
是重要的抗原提呈细胞
C.
表达 MHC-II 类分子
D.
表达 MHC-I 类分子
E.
具有免疫调节作用
【多选题】关于树突状细胞，正确的是（）
A.
可与单核细胞有共同的祖细胞
B.
可与T细胞有共同的祖细胞
C.
广泛分布全身各脏器
D.
外周血，脾脏含量很少
E.
膜表面特异性抗原识别受体
【单选题】有如下事件过程：Private Sub Form_Load() Show Dim Arr() As Variant Arr = Array(1, 3, 5, 7, 9, 11, 13, 15) Call converse(Arr) For i = 0 To 7 Print arr(i); Next iEnd Sub 以上程序的功能是，通过调用Converse过程，将数组Arr中的元素逆序存放并输出...
A.
Private Sub converse(dim a() as Variant ) Dim T For i = LBound(A) To UBound(A) T = a(i) a(i) = a(UBound(A) - i) a(UBound(A) - i) = T Next i End Sub
B.
Private Sub converse(dim a() as Variant) Dim T Dim J As Integer J = (LBound(A) + UBound(A)) / 2 For i = LBound(A) To J T = a(i) a(i) = a(UBound(A) - i) a(UBound(A) - i) = T Next i End Sub
C.
Private Sub converse(a() As Variant) Dim T For i = LBound(A) To UBound(A) T = a(i) a(i) = a(UBound(A) - i) a(UBound(A) - i) = T Next i End Sub
D.
Private Sub converse(a() As Variant) Dim T Dim J As Integer J = Int((LBound(A) + UBound(A)) / 2) For i = LBound(A) To J T = a(i) a(i) = a(UBound(A) - i) a(UBound(A) - i) = T Next i End Sub
参考解析：
题目纠错 0
发布
